Exercise · ZW-RESIDUE-010 · ★★★ Advanced

A function has a pole at \(z_0\) and its Laurent series on \(0<|z-z_0|<r\) is \(\frac{3}{(z-z_0)^2}+\frac{5}{z-z_0}+7+\cdots\). What is \(\oint_{|z-z_0|=r/2}f\,dz\)?

Choose one option.

Show answer
  • B. \(10\pi i\)

Explanation

Only the \(\frac{5}{z-z_0}\) term survives integration: the integral is \(2\pi i\cdot a_{-1}=10\pi i\). The \(\frac{3}{(z-z_0)^2}\) term integrates to \(0\).

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Review the concept: Residue

The residue of a function \(f\) at an isolated singularity \(z_0\) is the coefficient \(a_{-1}\) of \((z-z_0)^{-1}\) in its Laurent series on a punctured disc of radius \(r\).

\[\operatorname{Res}(f,z_0)=a_{-1}=\frac{1}{2\pi i}\oint_{|z-z_0|=r/2}f(z)\,dz\]

More practice problems: residue

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