Exercise · ZW-ROLLES-THEOREM-013 · ★☆☆ Basic
Which hypothesis of Rolle's theorem fails for \(f(x)=x\) on \([0,1]\)?
Choose one option.
Show answer
- A. \(f(0)=f(1)\)
Explanation
\(f(0)=0\ne1=f(1)\), and indeed \(f'(x)=1\) never vanishes.
Review the concept: Rolle's theorem
If \(f\) is continuous on \([a,b]\), differentiable on \((a,b)\) and \(f(a)=f(b)\), there is at least one \(c\in(a,b)\) with \(f^{\prime}(c)=0\).
\[f(a)=f(b)\ \Rightarrow\ \exists\,c\in(a,b):\ f'(c)=0\]
More practice problems: rolle's theorem
- ZW-ROLLES-THEOREM-001 Verify Rolle's theorem for f(x)=x^2 - 4 x + 3 on [1,3] and find c with f'(c)=0.
- ZW-ROLLES-THEOREM-002 Verify Rolle's theorem for f(x)=sin x on [0,π] and find c with f'(c)=0.
- ZW-ROLLES-THEOREM-003 Which of these conditions is NOT a hypothesis of Rolle's theorem?
- ZW-ROLLES-THEOREM-004 In which of these cases do the hypotheses of Rolle's theorem NOT hold?
- ZW-ROLLES-THEOREM-005 If the hypotheses of Rolle's theorem hold on [a,b], what does the conclusion state?
- ZW-ROLLES-THEOREM-006 For f(x)=x^3-x on [-1,1], which of these values satisfies f'(c)=0 with c∈(-1,1)?
- ZW-ROLLES-THEOREM-007 For f(x)=x^2 on [0,2], which c∈(0,2) satisfies f'(c)=(f(2)-f(0))/(2-0)?
- ZW-ROLLES-THEOREM-008 Which of these cases is continuous with f(a)=f(b), but has no c∈(a,b) with f'(c)=0?