Exercise · ZW-ROLLES-THEOREM-014 · ★★☆ Intermediate

For \(f(x)=x^3-x\) on \([0,1]\), what is the point \(c\in(0,1)\) with \(f'(c)=0\)?

Choose one option.

Show answer
  • C. \(c=\tfrac{1}{\sqrt3}\)

Explanation

\(f(0)=f(1)=0\) and \(f'(x)=3x^2-1=0\) gives \(x=\pm\tfrac1{\sqrt3}\); only the positive one lies in \((0,1)\).

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Review the concept: Rolle's theorem

If \(f\) is continuous on \([a,b]\), differentiable on \((a,b)\) and \(f(a)=f(b)\), there is at least one \(c\in(a,b)\) with \(f^{\prime}(c)=0\).

\[f(a)=f(b)\ \Rightarrow\ \exists\,c\in(a,b):\ f'(c)=0\]

More practice problems: rolle's theorem

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