Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-001 · ★☆☆ Basic

Which of these spaces, with the usual distance, is sequentially compact?

Choose one option.

Show answer
  • C. \([0,1]\)

Explanation

In \([0,1]\) every sequence is bounded, so it has a convergent subsequence (Bolzano-Weierstrass), and the limit stays in \([0,1]\) because it is closed. The other spaces contain sequences with no subsequence converging inside the space.

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Review the concept: Sequential compactness

A metric space \(X\) is sequentially compact if every sequence \((x_n)\) in \(X\) has a subsequence \((x_{n_k})\) converging to a point \(x\in X\).

\[\forall (x_n)\subseteq X\ \ \exists\, n_1

More practice problems: sequential compactness

ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-002 →