Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-008 · ★★☆ Intermediate

For a metric space \(X\), which statement is true?

Choose one option.

Show answer
  • A. \(X\) is compact if and only if it is sequentially compact

Explanation

In metric spaces the two notions coincide. The other statements fail for \([0,1]\), which is compact, infinite, not discrete and bounded.

Study General topology in ZWMath →

Review the concept: Sequential compactness

A metric space \(X\) is sequentially compact if every sequence \((x_n)\) in \(X\) has a subsequence \((x_{n_k})\) converging to a point \(x\in X\).

\[\forall (x_n)\subseteq X\ \ \exists\, n_1

More practice problems: sequential compactness

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