Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-007 · ★★☆ Intermediate
Let \(x_n=(-1)^n\,\dfrac{n}{n+1}\) in \([-1,1]\). To which values do its convergent subsequences converge?
Choose one option.
Show answer
- D. To \(1\) and to \(-1\)
Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-007 · ★★☆ Intermediate
Choose one option.
The even terms are \(\tfrac{n}{n+1}\to1\) and the odd ones \(-\tfrac{n}{n+1}\to-1\). Every convergent subsequence has infinitely many terms of one kind, so its limit is \(1\) or \(-1\); the sequence itself does not converge.
A metric space \(X\) is sequentially compact if every sequence \((x_n)\) in \(X\) has a subsequence \((x_{n_k})\) converging to a point \(x\in X\).
← ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-006 ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-008 →