Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-007 · ★★☆ Intermediate

Let \(x_n=(-1)^n\,\dfrac{n}{n+1}\) in \([-1,1]\). To which values do its convergent subsequences converge?

Choose one option.

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  • D. To \(1\) and to \(-1\)

Explanation

The even terms are \(\tfrac{n}{n+1}\to1\) and the odd ones \(-\tfrac{n}{n+1}\to-1\). Every convergent subsequence has infinitely many terms of one kind, so its limit is \(1\) or \(-1\); the sequence itself does not converge.

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Review the concept: Sequential compactness

A metric space \(X\) is sequentially compact if every sequence \((x_n)\) in \(X\) has a subsequence \((x_{n_k})\) converging to a point \(x\in X\).

\[\forall (x_n)\subseteq X\ \ \exists\, n_1

More practice problems: sequential compactness

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