Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-003 · ★☆☆ Basic
To prove that \((0,1)\) is not sequentially compact, which sequence works?
Choose one option.
Show answer
- B. \(x_n=1/n\)
Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-003 · ★☆☆ Basic
Choose one option.
Every subsequence of \(1/n\) tends to \(0\notin(0,1)\). The others have subsequences converging inside \((0,1)\): to \(\tfrac12\), to \(\tfrac14\) and \(\tfrac34\), and to \(\tfrac12\) respectively.
A metric space \(X\) is sequentially compact if every sequence \((x_n)\) in \(X\) has a subsequence \((x_{n_k})\) converging to a point \(x\in X\).
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