Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-003 · ★☆☆ Basic

To prove that \((0,1)\) is not sequentially compact, which sequence works?

Choose one option.

Show answer
  • B. \(x_n=1/n\)

Explanation

Every subsequence of \(1/n\) tends to \(0\notin(0,1)\). The others have subsequences converging inside \((0,1)\): to \(\tfrac12\), to \(\tfrac14\) and \(\tfrac34\), and to \(\tfrac12\) respectively.

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Review the concept: Sequential compactness

A metric space \(X\) is sequentially compact if every sequence \((x_n)\) in \(X\) has a subsequence \((x_{n_k})\) converging to a point \(x\in X\).

\[\forall (x_n)\subseteq X\ \ \exists\, n_1

More practice problems: sequential compactness

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