Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-006 · ★★☆ Intermediate
Let \(x_n=\cos\!\big(\tfrac{n\pi}{2}\big)\) in \([-1,1]\). Which values are limits of some subsequence?
Choose one option.
Show answer
- B. \(\{-1,\,0,\,1\}\)
Exercise · ZW-SEQUENTIAL-COMPACTNESS-METRIC-SPACES-006 · ★★☆ Intermediate
Choose one option.
The values of the sequence are \(0,-1,0,1\) repeated with period \(4\): each appears infinitely often, so each is the limit of a constant subsequence.
A metric space \(X\) is sequentially compact if every sequence \((x_n)\) in \(X\) has a subsequence \((x_{n_k})\) converging to a point \(x\in X\).
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