Exercise · ZW-SEQUENTIAL-CONTINUITY-002 · ★☆☆ Basic
Let \(f(x)=1\) if \(x\ge0\) and \(f(x)=-1\) if \(x<0\). Which sequence converging to \(0\) shows that \(f\) is not continuous at \(0\)?
Choose one option.
Show answer
- C. \(x_n=-1/n\)
Exercise · ZW-SEQUENTIAL-CONTINUITY-002 · ★☆☆ Basic
Choose one option.
With \(x_n=-1/n\to0\) we get \(f(x_n)=-1\not\to f(0)=1\). The other sequences have \(x_n\ge0\) and always give \(1\).
A function \(f\) is sequentially continuous at \(c\) if, for every sequence \((x_n)\) in the domain converging to \(c\), the sequence of images \(f(x_n)\) converges to \(f(c)\).
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