Exercise · ZW-SEQUENTIAL-CONTINUITY-003 · ★☆☆ Basic

Let \(f\) be the Dirichlet function (\(1\) at rationals, \(0\) at irrationals) and \(x_n=\sqrt2/n\). What is \(\lim f(x_n)\)?

Choose one option.

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  • B. \(0\)

Explanation

Each \(\sqrt2/n\) is irrational, so \(f(x_n)=0\) for all \(n\). Since \(x_n\to0\) and \(f(0)=1\), \(f\) is not continuous at \(0\).

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Review the concept: Sequential continuity

A function \(f\) is sequentially continuous at \(c\) if, for every sequence \((x_n)\) in the domain converging to \(c\), the sequence of images \(f(x_n)\) converges to \(f(c)\).

\[x_n\to c\ \Longrightarrow\ f(x_n)\to f(c)\]

More practice problems: sequential continuity

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