On \([0,3]\) the factor \(|x+y|\) is at most \(6\), so \(L=6\) works and is the smallest possible (approached with \(x,y\) near \(3\)). Hence \(\delta=\varepsilon/6\) works. \(L=3\) and \(L=5\) fail; \(L=9\) works but is not the smallest.
A function \(f\) is uniformly continuous on a set \(A\) if for each \(\varepsilon>0\) there is a \(\delta>0\), valid for all points at once, that controls \(|f(x)-f(y)|\) by \(|x-y|\) in \(A\).