Exercise · ZW-UNIFORM-CONVERGENCE-003 · ★★☆ Intermediate

Compute \(\sup_{x\in[0,1)}|x^n-0|\).

Choose one option.

Show answer
  • C. \(1\)

Explanation

As \(x\to1^-\), \(x^n\to1\), so the supremum is \(1\) for every \(n\) (it is not attained). Since it does not tend to \(0\), the convergence to \(0\) on \([0,1)\) is not uniform.

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Review the concept: Uniform convergence

A sequence of functions \(f_n\) converges uniformly to \(f\) on a set \(A\) if, for every \(\varepsilon>0\), a single index \(N\) works for all points of \(A\).

\[\forall\varepsilon>0\ \exists N:\ n\ge N\Rightarrow|f_n(x)-f(x)|<\varepsilon\ \ \forall x\in A\]

More practice problems: uniform convergence

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