Exercise · ZW-UNIFORM-CONVERGENCE-005 · ★★☆ Intermediate

Let \(f_n(x)=\frac{\sin(nx)}{n}\) on \(\mathbb R\). What happens?

Choose one option.

Show answer
  • A. It converges uniformly to \(0\), since \(|f_n(x)|\le\frac1n\).

Explanation

Since \(|\sin(nx)|\le1\), we get \(\sup_x|f_n(x)|\le1/n\to0\). The bound does not depend on \(x\), which is exactly uniformity.

Study Real analysis in ZWMath →

Review the concept: Uniform convergence

A sequence of functions \(f_n\) converges uniformly to \(f\) on a set \(A\) if, for every \(\varepsilon>0\), a single index \(N\) works for all points of \(A\).

\[\forall\varepsilon>0\ \exists N:\ n\ge N\Rightarrow|f_n(x)-f(x)|<\varepsilon\ \ \forall x\in A\]

More practice problems: uniform convergence

← ZW-UNIFORM-CONVERGENCE-004 ZW-UNIFORM-CONVERGENCE-006 →