Rings and domains · Definition
Zero divisor
In the integers a zero product forces a zero factor; in other rings that can fail, and zero divisors measure how much.
Definition
A zero divisor of a ring \(R\) is an element \(a\neq0\) for which there is another element \(b\neq0\) of \(R\) whose product with \(a\) is zero.
Zero divisors appear when the product of two nonzero elements vanishes. In \(\mathbb{Z}_6\) we have \(2\cdot3=0\), so 2 and 3 are zero divisors; in \(\mathbb{Z}_7\) there are none. In general, in \(\mathbb{Z}_n\) an element \(a\neq0\) is a zero divisor exactly when \(\gcd(a,n)>1\), and a unit when \(\gcd(a,n)=1\): every nonzero element is one or the other.
A unit is never a zero divisor, since if \(uv=0\) multiplying by \(u^{-1}\) gives \(v=0\). In a finite commutative ring with identity the converse holds: every nonzero element is a unit or a zero divisor. Beyond finite rings it can fail: in \(\mathbb{Z}\) the number 2 is neither a unit nor a zero divisor.
The practical effect is cancellation. If \(a\) is not a zero divisor and \(ab=ac\), then \(a(b-c)=0\) forces \(b=c\); if it is one, cancellation is lost: in \(\mathbb{Z}_8\), \(4\cdot1=4\cdot3\) without \(1=3\). An integral domain is precisely a commutative ring with identity and no zero divisors, the natural setting for factoring and solving polynomial equations.
Two typical mistakes: zero is not called a zero divisor by convention (the definition requires \(a\neq0\)), and zero divisors do not require noncommutativity: \(\mathbb{Z}_6\) already has them. In \(2\times2\) matrices, products like \(E_{11}E_{22}=0\) produce them easily.
Think about it
Why can a field not have zero divisors?
Because every nonzero element is a unit, and a unit is never a zero divisor.
If \(ab=0\) in \(\mathbb{Z}_n\) with \(n=pq\) (distinct primes), which nonzero pair shows it?
The pair \(a=p\), \(b=q\): both are nonzero and their product is \(n\equiv0\).
Exercises 10
- In \(\mathbb{Z}_{12}\), which of these elements is a zero divisor?
- How many zero divisors does \(\mathbb{Z}_{10}\) have?
- Which of these rings has no zero divisors?
- In \(\mathbb{Z}_{15}\), which \(b\neq0\) satisfies \(6b=0\)?
- In the ring of \(2\times2\) real matrices, which of these matrices is a zero divisor?
- Which statement is true in a ring \(R\) with identity, \(R\neq0\)?
- In \(\mathbb{Z}\times\mathbb{Z}\), which of these elements is a zero divisor?
- In \(\mathbb{Z}_{8}\), which pair with \(x\neq y\) satisfies \(4x=4y\)?
- How many zero divisors does \(\mathbb{Z}_{21}\) have?
- If \(a\neq0\) satisfies \(a^2=0\) in a ring, what is \(a\)?
What comes next
References
- David S. Dummit, Richard M. Foote, Abstract Algebra, 3rd edition, Wiley, 2004. §7.1
- Joseph A. Gallian, Contemporary Abstract Algebra, 9th edition, Cengage, 2017. cap. 13
- I. N. Herstein, Abstract Algebra, 3rd edition, Wiley, 1996. §3.2
- John B. Fraleigh, A First Course in Abstract Algebra, 7th edition, Pearson, 2002. §19