Actions and Sylow theorems · Definition
Orbit-stabilizer theorem
Before you start you need to know
This theorem turns a counting problem in \(X\) into a divisibility problem in \(G\), and is the basic tool for counting with symmetries.
Definition
For a finite group \(G\) acting on \(X\) and an element \(x\in X\), the size of the orbit of \(x\) is the index of its stabilizer in \(G\).
The idea is that each point of the orbit of \(x\) corresponds to a coset of the stabilizer: \(g\,\mathrm{Stab}(x)\) is matched with \(g\cdot x\). The assignment is well defined because \(g\cdot x=g'\cdot x\) is equivalent to \(g^{-1}g'\in\mathrm{Stab}(x)\), it is injective by that same equivalence, and surjective by the definition of the orbit. So the number of elements of the orbit equals the number of cosets, that is, the index.
Since the index of a subgroup is \(|G|/|H|\) by Lagrange's theorem, we get \(|\mathrm{Orb}(x)|\cdot|\mathrm{Stab}(x)|=|G|\). An immediate consequence: the size of every orbit divides \(|G|\), and if the orbit is known the stabilizer follows, and vice versa.
Guiding example: the symmetry group of the square has order \(8\) and acts on the \(4\) vertices in one orbit; so the stabilizer of a vertex has \(8/4=2\) elements, the identity and one reflection. The same count in \(S_n\) acting on \(\{1,\dots,n\}\) shows that the stabilizer of a point has \((n-1)!\) elements.
The theorem needs \(G\) finite to write quotients of orders, although the bijection between the orbit and the cosets always holds. It is later used to count orbits, to study \(p\)-groups and in the Sylow theorems.
Think about it
A group of order \(7\) acts on a set of \(10\) elements. What is the minimum number of orbits of size \(1\)?
Orbits have size \(1\) or \(7\), and \(10=7a+b\) with \(b\) fixed points. Since \(a\le1\), \(b\ge3\): at least \(3\) fixed points.
Exercises 10
- A group of order \(12\) acts on a set and the stabilizer of \(x\) has \(3\) elements. How many elements does the orbit of \(x\) have?
- A group of order \(20\) acts and the orbit of \(x\) has \(5\) elements. How many elements does the stabilizer of \(x\) have?
- \(S_4\) acts on \(\{1,2,3,4\}\) by \(g\cdot x=g(x)\). How many elements does the stabilizer of \(1\) have?
- A group of order \(15\) acts on a set. Which of these CANNOT be the size of an orbit?
- \(S_5\) acts on the \(3\)-element subsets of \(\{1,2,3,4,5\}\), all forming a single orbit. How many elements does the stabilizer of \(\{1,2,3\}\) have?
- The rotation group of the cube has order \(24\) and acts on its \(8\) vertices, all in one orbit. How many rotations fix a given vertex?
- For an action of a finite group \(G\) on \(X\) and \(x\in X\), which statement is true?
- A group of order \(60\) acts on \(X\) with a single orbit, and the stabilizer of each point has \(5\) elements. How many elements does \(X\) have?
- A group of order \(9\) acts on a set of \(7\) elements. What is the minimum number of fixed points (one-element orbits) there must be?
- A group of order \(24\) acts transitively on a set of \(6\) elements. If \(x,y\in X\), how many \(g\in G\) satisfy \(g\cdot x=y\)?
What comes next
References
- David S. Dummit, Richard M. Foote, Abstract Algebra, 3rd edition, Wiley, 2004. §4.1
- John B. Fraleigh, A First Course in Abstract Algebra, 7th edition, Pearson, 2002. §16
- Joseph A. Gallian, Contemporary Abstract Algebra, 9th edition, Cengage, 2017. cap. 29