Exercise · ZW-CONCAVITY-AND-INFLECTION-POINTS-003 · ★★★ Advanced

At which values of x does \(f(x)=x^{4} - 6 x^{2}\) have inflection points?

Choose one option.

Show answer
  • A. \(x=-1,\ x=1\)

Explanation

Compute \(f''(x)=12 \left(x^{2} - 1\right)=12 \left(x - 1\right) \left(x + 1\right)\), which vanishes at \(x=-1,\ x=1\) and changes sign at both. They are the inflection points.

Study Calculus in ZWMath →

Review the concept: Concavity and inflection points

If \(f^{\prime\prime}>0\) on an interval, the graph is concave up; if \(f^{\prime\prime}<0\), concave down. An inflection point is where the concavity changes, and there \(f^{\prime\prime}(c)=0\) or does not exist.

\[\begin{gathered}f''>0\ \Rightarrow\ \text{concave up}\\ f''<0\ \Rightarrow\ \text{concave down}\end{gathered}\]

More practice problems: concavity and inflection points

← ZW-CONCAVITY-AND-INFLECTION-POINTS-002 ZW-CONCAVITY-AND-INFLECTION-POINTS-004 →