Exercise · ZW-CONCAVITY-AND-INFLECTION-POINTS-007 · ★★☆ Intermediate

On which interval is the graph of \(f(x)=x^{3}\) concave up?

Choose one option.

Show answer
  • A. \((0,\infty)\)

Explanation

We have \(f''(x)=6x\), which is positive only when \(x>0\). So the graph is concave up on \((0,\infty)\).

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Review the concept: Concavity and inflection points

If \(f^{\prime\prime}>0\) on an interval, the graph is concave up; if \(f^{\prime\prime}<0\), concave down. An inflection point is where the concavity changes, and there \(f^{\prime\prime}(c)=0\) or does not exist.

\[\begin{gathered}f''>0\ \Rightarrow\ \text{concave up}\\ f''<0\ \Rightarrow\ \text{concave down}\end{gathered}\]

More practice problems: concavity and inflection points

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