Exercise · ZW-CONCAVITY-AND-INFLECTION-POINTS-004 · ★★★ Advanced
For \(f(x)=x^{4}\), \(f''(0)=0\). Does f have an inflection point at x = 0?
Choose one option.
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- D. No: \(f''(x)=12x^{2}\) does not change sign at 0
Exercise · ZW-CONCAVITY-AND-INFLECTION-POINTS-004 · ★★★ Advanced
Choose one option.
Having \(f''(c)=0\) is not enough: f'' must change sign. Here \(f''(x)=12x^{2}\ge0\) on both sides of 0, the graph stays concave up and there is no inflection (there is a minimum).
If \(f^{\prime\prime}>0\) on an interval, the graph is concave up; if \(f^{\prime\prime}<0\), concave down. An inflection point is where the concavity changes, and there \(f^{\prime\prime}(c)=0\) or does not exist.
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