Exercise · ZW-CONCAVITY-AND-INFLECTION-POINTS-004 · ★★★ Advanced

For \(f(x)=x^{4}\), \(f''(0)=0\). Does f have an inflection point at x = 0?

Choose one option.

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  • D. No: \(f''(x)=12x^{2}\) does not change sign at 0

Explanation

Having \(f''(c)=0\) is not enough: f'' must change sign. Here \(f''(x)=12x^{2}\ge0\) on both sides of 0, the graph stays concave up and there is no inflection (there is a minimum).

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Review the concept: Concavity and inflection points

If \(f^{\prime\prime}>0\) on an interval, the graph is concave up; if \(f^{\prime\prime}<0\), concave down. An inflection point is where the concavity changes, and there \(f^{\prime\prime}(c)=0\) or does not exist.

\[\begin{gathered}f''>0\ \Rightarrow\ \text{concave up}\\ f''<0\ \Rightarrow\ \text{concave down}\end{gathered}\]

More practice problems: concavity and inflection points

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