Exercise · ZW-DIFFERENTIABILITY-AND-CONTINUITY-005 · ★★☆ Intermediate

Let \(f(x)=x^2\sin(1/x)\) for \(x\ne0\) and \(f(0)=0\). What is \(f'(0)\)?

Choose one option.

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  • C. \(0\)

Explanation

The quotient is \(h\sin(1/h)\), and \(|h\sin(1/h)|\le|h|\to0\). Hence \(f'(0)=0\), even though \(f'\) oscillates near \(0\).

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Review the concept: Differentiability and continuity

If a function \(f\) is differentiable at a point \(c\), then \(f\) is continuous at \(c\). The converse is false.

\[f'(c)\text{ exists}\ \Longrightarrow\ \lim_{x\to c}f(x)=f(c)\]

More practice problems: differentiability and continuity

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