Exercise · ZW-DIFFERENTIABILITY-AND-CONTINUITY-008 · ★★☆ Intermediate

Let \(f(x)=1\) if \(x\ge0\) and \(f(x)=0\) if \(x<0\). Is \(f\) differentiable at \(0\)?

Choose one option.

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  • B. No, because it is not continuous at \(0\).

Explanation

The jump at \(0\) breaks continuity: \(\lim_{x\to0^-}f=0\ne1=f(0)\). Without continuity there can be no derivative.

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Review the concept: Differentiability and continuity

If a function \(f\) is differentiable at a point \(c\), then \(f\) is continuous at \(c\). The converse is false.

\[f'(c)\text{ exists}\ \Longrightarrow\ \lim_{x\to c}f(x)=f(c)\]

More practice problems: differentiability and continuity

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