Exercise · ZW-DIRECT-PRODUCT-OF-GROUPS-010 · ★★★ Advanced
How many elements of order 4 does \(\mathbb{Z}_4\times\mathbb{Z}_2\) have?
Choose one option.
Show answer
- A. 4
Exercise · ZW-DIRECT-PRODUCT-OF-GROUPS-010 · ★★★ Advanced
Choose one option.
The order of \((a,b)\) is \(\operatorname{lcm}(\operatorname{ord}a,\operatorname{ord}b)\), and \(\operatorname{ord}b\le2\), so the order is 4 exactly when \(a\) has order 4, that is, \(a\in\{1,3\}\). With 2 choices for \(b\) this gives \(2\cdot2=4\) elements.
The direct product \(G\times H\) of two groups \(G\) and \(H\) is the set of pairs \((g,h)\), with \(g\in G\) and \(h\in H\), with the operation defined componentwise.