Exercise · ZW-DIRECT-PRODUCT-OF-GROUPS-010 · ★★★ Advanced

How many elements of order 4 does \(\mathbb{Z}_4\times\mathbb{Z}_2\) have?

Choose one option.

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  • A. 4

Explanation

The order of \((a,b)\) is \(\operatorname{lcm}(\operatorname{ord}a,\operatorname{ord}b)\), and \(\operatorname{ord}b\le2\), so the order is 4 exactly when \(a\) has order 4, that is, \(a\in\{1,3\}\). With 2 choices for \(b\) this gives \(2\cdot2=4\) elements.

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Review the concept: Direct product of groups

The direct product \(G\times H\) of two groups \(G\) and \(H\) is the set of pairs \((g,h)\), with \(g\in G\) and \(h\in H\), with the operation defined componentwise.

\[(g_1,h_1)(g_2,h_2)=(g_1g_2,\;h_1h_2)\]

More practice problems: direct product of groups

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