Exercise · ZW-EUCLIDEAN-DOMAIN-009 · ★★★ Advanced
To prove that an ideal \(I\neq0\) of a Euclidean domain is principal, which element is taken as generator?
Choose one option.
Show answer
- C. A nonzero element of \(I\) with minimal norm
Exercise · ZW-EUCLIDEAN-DOMAIN-009 · ★★★ Advanced
Choose one option.
If \(d\) has minimal norm and \(a\in I\), divide \(a=dq+r\). Then \(r=a-dq\in I\) and, if nonzero, it would have smaller norm than \(d\), absurd. So \(a\in(d)\). A maximal norm does not even exist in general.
An integral domain \(D\) with a norm \(N\) (a function from \(D\setminus\{0\}\) to the nonnegative integers) allowing division of \(a\) by \(b\neq0\) with quotient \(q\) and remainder \(r\) zero or of smaller norm than \(b\).