Exercise · ZW-EUCLIDEAN-DOMAIN-009 · ★★★ Advanced

To prove that an ideal \(I\neq0\) of a Euclidean domain is principal, which element is taken as generator?

Choose one option.

Show answer
  • C. A nonzero element of \(I\) with minimal norm

Explanation

If \(d\) has minimal norm and \(a\in I\), divide \(a=dq+r\). Then \(r=a-dq\in I\) and, if nonzero, it would have smaller norm than \(d\), absurd. So \(a\in(d)\). A maximal norm does not even exist in general.

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Review the concept: Euclidean domain

An integral domain \(D\) with a norm \(N\) (a function from \(D\setminus\{0\}\) to the nonnegative integers) allowing division of \(a\) by \(b\neq0\) with quotient \(q\) and remainder \(r\) zero or of smaller norm than \(b\).

\[a=bq+r,\qquad r=0\ \text{ or }\ N(r)

More practice problems: euclidean domain

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