Exercise · ZW-FIRST-ISOMORPHISM-THEOREM-FOR-RINGS-006 · ★★☆ Intermediate

There is a surjective homomorphism \(\mathbb{Z}_{30}\to \mathbb{Z}_{5}\). How many elements does its kernel have?

Choose one option.

Show answer
  • C. \(6\)

Explanation

By the first theorem \(\mathbb{Z}_{30}/\ker\varphi\cong \mathbb{Z}_{5}\), so \(|\ker\varphi|=30/5=6\). The kernel is \(\{0,5,10,15,20,25\}\).

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Review the concept: First isomorphism theorem for rings

If \(\varphi\colon R\to S\) is a ring homomorphism with kernel \(\ker\varphi\), the quotient ring of \(R\) by \(\ker\varphi\) is isomorphic to the image of \(\varphi\).

\[R/\ker\varphi\;\cong\;\varphi(R)\]

More practice problems: first isomorphism theorem for rings

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