Exercise · ZW-FIRST-ISOMORPHISM-THEOREM-FOR-RINGS-006 · ★★☆ Intermediate
There is a surjective homomorphism \(\mathbb{Z}_{30}\to \mathbb{Z}_{5}\). How many elements does its kernel have?
Choose one option.
Show answer
- C. \(6\)
Exercise · ZW-FIRST-ISOMORPHISM-THEOREM-FOR-RINGS-006 · ★★☆ Intermediate
Choose one option.
By the first theorem \(\mathbb{Z}_{30}/\ker\varphi\cong \mathbb{Z}_{5}\), so \(|\ker\varphi|=30/5=6\). The kernel is \(\{0,5,10,15,20,25\}\).
If \(\varphi\colon R\to S\) is a ring homomorphism with kernel \(\ker\varphi\), the quotient ring of \(R\) by \(\ker\varphi\) is isomorphic to the image of \(\varphi\).
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