Exercise · ZW-FIRST-ISOMORPHISM-THEOREM-FOR-RINGS-002 · ★☆☆ Basic

Let \(\pi\colon \mathbb{Z}\times \mathbb{Z}\to \mathbb{Z}\) be given by \(\pi(a,b)=a\). To which ring is \((\mathbb{Z}\times \mathbb{Z})/\ker\pi\) isomorphic?

Choose one option.

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  • C. \(\mathbb{Z}\)

Explanation

Since \(\pi\) is a surjective homomorphism, the first theorem says the quotient is isomorphic to the image, which is all of \(\mathbb{Z}\). Here \(\ker\pi=\{0\}\times \mathbb{Z}\).

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Review the concept: First isomorphism theorem for rings

If \(\varphi\colon R\to S\) is a ring homomorphism with kernel \(\ker\varphi\), the quotient ring of \(R\) by \(\ker\varphi\) is isomorphic to the image of \(\varphi\).

\[R/\ker\varphi\;\cong\;\varphi(R)\]

More practice problems: first isomorphism theorem for rings

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