Exercise · ZW-GROUP-007 · ★★☆ Intermediate
\(\mathbb{N}=\{0,1,2,\ldots\}\) with the usual addition is not a group because...
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- D. Not every natural has an additive inverse in ℕ
Exercise · ZW-GROUP-007 · ★★☆ Intermediate
Choose one option.
With \(0\) in the set, \(\mathbb{N}\) is closed under addition, addition is associative and \(0\) is the identity. What fails is that, for example, \(3\) has no natural \(n\) with \(3+n=0\).
A group is a nonempty set \(G\) together with an associative binary operation, with an identity element and an inverse for every element.