Exercise · ZW-GROUP-007 · ★★☆ Intermediate

\(\mathbb{N}=\{0,1,2,\ldots\}\) with the usual addition is not a group because...

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  • D. Not every natural has an additive inverse in ℕ

Explanation

With \(0\) in the set, \(\mathbb{N}\) is closed under addition, addition is associative and \(0\) is the identity. What fails is that, for example, \(3\) has no natural \(n\) with \(3+n=0\).

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Review the concept: Group

A group is a nonempty set \(G\) together with an associative binary operation, with an identity element and an inverse for every element.

\[(G,\ast)\]

More practice problems: group

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