Exercise · ZW-P-GROUP-003 · ★☆☆ Basic
A subgroup of a group of order \(16\) cannot have order:
Choose one option.
Show answer
- A. \(6\)
Explanation
The order of a subgroup divides \(16=2^4\), so it is a power of \(2\). The number \(6\) is not, and it does not divide \(16\).
Review the concept: p-group
A \(p\)-group is a finite group \(G\) whose order is a power \(p^n\), with \(n\ge1\), of a prime number \(p\).
\[|G|=p^{n}\]
More practice problems: p-group
- ZW-P-GROUP-001 Which of these groups is a 2-group?
- ZW-P-GROUP-002 In a group of order 125, which cannot be the order of an element?
- ZW-P-GROUP-004 Is ℤ_9×ℤ_3 a p-group? For which prime p?
- ZW-P-GROUP-005 A group of order 81 has a subgroup of order 9. What is the index of that subgroup?
- ZW-P-GROUP-006 For which primes p is a group of order 12 a p-group?
- ZW-P-GROUP-007 A finite group has an element of order 15. Can it be a p-group?
- ZW-P-GROUP-008 A group of order 25 acts on a set of 11 elements. What is the minimum number of fixed points?
- ZW-P-GROUP-009 Select the true statement about a finite p-group G.