Exercise · ZW-POLYNOMIAL-DIVISION-ALGORITHM-006 · ★★☆ Intermediate
What is the remainder of dividing \(x^{101}+x^2+1\) by \(x+1\) in \(\mathbb{Q}[x]\)?
Choose one option.
Show answer
- C. \(1\)
Exercise · ZW-POLYNOMIAL-DIVISION-ALGORITHM-006 · ★★☆ Intermediate
Choose one option.
The remainder is \(f(-1)=(-1)^{101}+1+1=1\), because the divisor has degree 1. Using \(f(1)=3\) mixes up the root of \(x-1\) with that of \(x+1\).
Given polynomials \(f\) and \(g\neq 0\) over a field \(F\), there exist a unique quotient \(q\) and a unique remainder \(r\) satisfying the equality below, with \(r\) zero or of degree less than that of \(g\).
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