Exercise · ZW-UNIQUE-FACTORIZATION-DOMAIN-008 · ★★☆ Intermediate
In \(\mathbb{Q}[x]\), how many irreducible factors (with multiplicity, up to associates) does \(x^4-x^2\) have?
Choose one option.
Show answer
- D. 4
Exercise · ZW-UNIQUE-FACTORIZATION-DOMAIN-008 · ★★☆ Intermediate
Choose one option.
We have \(x^4-x^2=x^2(x-1)(x+1)\): the factor \(x\) appears twice and there are two other distinct ones, 4 in total.
An integral domain \(D\) in which every nonzero nonunit element \(a\) is a product of irreducibles \(p_i\), and this factorization is unique up to order and associates.
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