Exercise · ZW-UNIQUE-FACTORIZATION-DOMAIN-008 · ★★☆ Intermediate

In \(\mathbb{Q}[x]\), how many irreducible factors (with multiplicity, up to associates) does \(x^4-x^2\) have?

Choose one option.

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  • D. 4

Explanation

We have \(x^4-x^2=x^2(x-1)(x+1)\): the factor \(x\) appears twice and there are two other distinct ones, 4 in total.

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Review the concept: Unique factorization domain

An integral domain \(D\) in which every nonzero nonunit element \(a\) is a product of irreducibles \(p_i\), and this factorization is unique up to order and associates.

\[a=p_1p_2\cdots p_r\]

More practice problems: unique factorization domain

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