Exercise · ZW-COMPLEX-CONTINUITY-010 · ★★★ Advanced
If \(f\) is continuous at \(z_0=1\) and \(f(1)=2i\), which is guaranteed?
Choose one option.
Show answer
- B. There is \(\delta>0\) with \(f(z)\neq 0\) whenever \(|z-1|<\delta\)
Exercise · ZW-COMPLEX-CONTINUITY-010 · ★★★ Advanced
Choose one option.
Taking \(\varepsilon=|f(1)|=2\) in the definition gives \(\delta\) with \(|f(z)-2i|<2\) near \(1\), which rules out \(f(z)=0\). Nothing more is guaranteed.
A function \(f\) is continuous at a point \(z_0\) of its domain if \(f(z)\) tends to the value \(f(z_0)\) as \(z\) tends to \(z_0\); it is continuous if it is so at every point of its domain.