Exercise · ZW-FIELD-OF-FRACTIONS-010 · ★★☆ Intermediate
In \(\operatorname{Frac}(\mathbb{Q}[x])\), what is the multiplicative inverse of \(x+1\)?
Choose one option.
Show answer
- A. \(\dfrac{1}{x+1}\)
Exercise · ZW-FIELD-OF-FRACTIONS-010 · ★★☆ Intermediate
Choose one option.
We have \((x+1)\cdot\tfrac1{x+1}=1\). That inverse is not a polynomial, which is why \(x+1\) is not a unit of \(\mathbb{Q}[x]\), but it is a unit in its field of fractions, where every nonzero element is invertible.
The field of fractions \(\operatorname{Frac}(D)\) of an integral domain \(D\) is the field made of the fractions \(a/b\), with \(a,b\in D\) and \(b\neq0\), where \(a/b=c/d\) when \(ad=bc\).