Exercise · ZW-FIELD-OF-FRACTIONS-010 · ★★☆ Intermediate

In \(\operatorname{Frac}(\mathbb{Q}[x])\), what is the multiplicative inverse of \(x+1\)?

Choose one option.

Show answer
  • A. \(\dfrac{1}{x+1}\)

Explanation

We have \((x+1)\cdot\tfrac1{x+1}=1\). That inverse is not a polynomial, which is why \(x+1\) is not a unit of \(\mathbb{Q}[x]\), but it is a unit in its field of fractions, where every nonzero element is invertible.

Study Modern algebra I in ZWMath →

Review the concept: Field of fractions

The field of fractions \(\operatorname{Frac}(D)\) of an integral domain \(D\) is the field made of the fractions \(a/b\), with \(a,b\in D\) and \(b\neq0\), where \(a/b=c/d\) when \(ad=bc\).

\[\frac ab=\frac cd\iff ad=bc,\qquad \frac ab+\frac cd=\frac{ad+bc}{bd},\qquad \frac ab\cdot\frac cd=\frac{ac}{bd}\]

More practice problems: field of fractions

← ZW-FIELD-OF-FRACTIONS-009