Exercise · ZW-GROUP-ACTION-005 · ★★☆ Intermediate

In \(S_3\) acting on \(\{1,2,3\}\), we have \(g\cdot1=2\) with \(g=(1\ 2\ 3)\). What is \(g^{-1}\cdot2\)?

Choose one option.

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  • A. \(1\)

Explanation

From \(g^{-1}\cdot(g\cdot1)=(g^{-1}g)\cdot1=e\cdot1=1\) we get \(g^{-1}\cdot2=1\).

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Review the concept: Group action

An action of a group \(G\) on a set \(X\) assigns to each \(g,h\in G\) and \(x\in X\) an element \(g\cdot x\in X\), so that the identity \(e\) moves nothing and the product of \(G\) acts by composition.

\[e\cdot x=x,\qquad (gh)\cdot x=g\cdot(h\cdot x)\]

More practice problems: group action

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