Exercise · ZW-GROUP-ACTION-007 · ★★☆ Intermediate
Let \(S_3\) act on itself by conjugation, \(g\cdot x=gxg^{-1}\). Compute \((1\ 2)\cdot(1\ 2\ 3)\).
Choose one option.
Show answer
- B. \((1\ 3\ 2)\)
Explanation
Conjugating by \((1\ 2)\) relabels the cycle, swapping \(1\) and \(2\): \((1\ 2\ 3)\) becomes \((2\ 1\ 3)=(1\ 3\ 2)\).
Review the concept: Group action
An action of a group \(G\) on a set \(X\) assigns to each \(g,h\in G\) and \(x\in X\) an element \(g\cdot x\in X\), so that the identity \(e\) moves nothing and the product of \(G\) acts by composition.
\[e\cdot x=x,\qquad (gh)\cdot x=g\cdot(h\cdot x)\]
More practice problems: group action
- ZW-GROUP-ACTION-001 The group S_3 acts on X=\1,2,3\ by g· x=g(x). If g=(1\ 2\ 3), what is g·1?
- ZW-GROUP-ACTION-002 In an action of G on X, what is e· x for x∈ X?
- ZW-GROUP-ACTION-003 Which of the following formulas defines an action of (mathbb Z,+) on mathbb Z?
- ZW-GROUP-ACTION-004 Let S_3 act on \1,2,3\, with g=(1\ 2\ 3) and h=(1\ 2). Compute (gh)·1, composing from right to left.
- ZW-GROUP-ACTION-005 In S_3 acting on \1,2,3\, we have g·1=2 with g=(1\ 2\ 3). What is g^-1·2?
- ZW-GROUP-ACTION-006 The group mathbb Z_6 acts on itself by g· x=g+x (mod 6). Compute 4·5.
- ZW-GROUP-ACTION-008 In an action of G on X, what kind of function is xmapsto g· x from X to X, for each g∈ G?
- ZW-GROUP-ACTION-009 mathbb Z_6 acts on mathbb Z_6 by n· x=x+2n (mod 6). How many distinct values does n·0 take as n ran…