Exercise · ZW-INVERSE-ELEMENT-010 · ★★☆ Intermediate
In a non-abelian group, the inverse of a still satisfies...
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- C. a∗a⁻¹=a⁻¹∗a=e
Exercise · ZW-INVERSE-ELEMENT-010 · ★★☆ Intermediate
Choose one option.
In a non-abelian group, inverses still satisfy a ∗ a⁻¹ = a⁻¹ ∗ a = e. What is lost is commutativity in general, not the existence of two-sided inverses.
Given \(a\in G\), an element \(b\in G\) is an inverse of \(a\) if operating in both orders gives the neutral element.