Exercise · ZW-INVERSE-ELEMENT-011 · ★★★ Advanced
In \(\mathbb{Z}_7\setminus\{0\}\) under multiplication, which \(x\) satisfies \(3\cdot x\cdot 3=1\)?
Choose one option.
Show answer
- B. 4
Exercise · ZW-INVERSE-ELEMENT-011 · ★★★ Advanced
Choose one option.
Since \(3\cdot 3=9\equiv 2\pmod 7\), the equation becomes \(2x\equiv 1\); since \(2\cdot 4=8\equiv 1\), \(x=4\). Check: \(3\cdot 4\cdot 3=36\equiv 1\pmod 7\).
Given \(a\in G\), an element \(b\in G\) is an inverse of \(a\) if operating in both orders gives the neutral element.