Exercise · ZW-ORBIT-AND-STABILIZER-004 · ★☆☆ Basic
The symmetry group of the square (order \(8\)) acts on its four vertices. How many elements does the stabilizer of a vertex have?
Choose one option.
A \(8\) B \(4\) C \(2\) D \(1\)
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Explanation Only the identity and the reflection across the diagonal through that vertex leave it fixed, so the stabilizer has \(2\) elements .
If a group \(G\) acts on a set \(X\), the orbit of \(x\in X\) is the set of all its images \(g\cdot x\), and its stabilizer is the subgroup of elements of \(G\) that leave it fixed.
\[\mathrm{Orb}(x)=\{g\cdot x : g\in G\},\qquad \mathrm{Stab}(x)=\{g\in G : g\cdot x=x\}\]
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