Exercise · ZW-ORBIT-AND-STABILIZER-007 · ★★☆ Intermediate

A group \(G\) acts on itself by \(g\cdot x=gx\). What is the stabilizer of an element \(x\)?

Choose one option.

Show answer
  • D. \(\{e\}\)

Explanation

If \(gx=x\), multiplying by \(x^{-1}\) gives \(g=e\). Only the identity fixes \(x\).

Study Modern algebra I in ZWMath →

Review the concept: Orbit and stabilizer

If a group \(G\) acts on a set \(X\), the orbit of \(x\in X\) is the set of all its images \(g\cdot x\), and its stabilizer is the subgroup of elements of \(G\) that leave it fixed.

\[\mathrm{Orb}(x)=\{g\cdot x : g\in G\},\qquad \mathrm{Stab}(x)=\{g\in G : g\cdot x=x\}\]

More practice problems: orbit and stabilizer

← ZW-ORBIT-AND-STABILIZER-006 ZW-ORBIT-AND-STABILIZER-008 →