Exercise · ZW-SIMPLE-GROUP-008 · ★★☆ Intermediate

For which subgroup \(N=\langle a\rangle\) of \(\mathbb{Z}_{12}\) is the quotient \(\mathbb{Z}_{12}/N\) simple?

Choose one option.

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  • A. \(\langle 2\rangle\)

Explanation

The quotient \(\mathbb{Z}_{12}/\langle a\rangle\) is cyclic of order \(\gcd(a,12)\). It is simple only when that order is prime: \(a=2\) gives \(\mathbb{Z}_2\); \(a=4\) gives \(\mathbb{Z}_4\), \(a=6\) gives \(\mathbb{Z}_6\) and \(a=0\) gives \(\mathbb{Z}_{12}\).

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Review the concept: Simple group

A simple group is a nontrivial group \(G\) whose only normal subgroups \(N\) are the trivial subgroup and \(G\) itself.

\[N\trianglelefteq G\ \Rightarrow\ N=\{e\}\ \text{ or }\ N=G\]

More practice problems: simple group

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