Exercise · ZW-CLASSIFICATION-OF-FINITE-ABELIAN-GROUPS-010 · ★★★ Advanced

Let \(G\) be an abelian group of order \(36\). Which statement is always true?

Choose one option.

Show answer
  • B. \(G\) has an element of order \(6\)

Explanation

Each candidate (with a part of order \(4\) and a part of order \(9\)) has an element of order \(2\) and another of order \(3\), whose product has order \(6\). By contrast, \(\mathbb{Z}_2\times\mathbb{Z}_2\times\mathbb{Z}_3\times\mathbb{Z}_3\) is not cyclic and has no element of order \(4\).

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Review the concept: Classification of finite abelian groups

Every finite abelian group \(G\) is isomorphic to a direct product of cyclic groups \(\mathbb{Z}_{p^k}\), with \(p\) prime and \(k\ge1\), unique up to order.

\[G\cong\mathbb{Z}_{p_1^{k_1}}\times\cdots\times\mathbb{Z}_{p_r^{k_r}}\]

More practice problems: classification of finite abelian groups

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