Exercise · ZW-KERNEL-OF-A-HOMOMORPHISM-004 · ★★☆ Intermediate

Let \(\varphi\colon\mathbb{Z}_{18}\to\mathbb{Z}_6\) with \(\varphi(x)=4x \bmod 6\). How many elements does its kernel have?

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  • A. 6

Explanation

We need \(4x\equiv0\pmod 6\), i.e. \(2x\equiv0\pmod 3\), i.e. \(x\equiv0\pmod 3\). In \(\mathbb{Z}_{18}\) there are \(6\) multiples of \(3\).

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Review the concept: Kernel of a homomorphism

The kernel of a group homomorphism \(\varphi\colon G\to H\) is the set of elements of \(G\) that \(\varphi\) sends to the identity \(e_H\) of \(H\).

\[\ker\varphi=\{g\in G:\ \varphi(g)=e_H\}\]

More practice problems: kernel of a homomorphism

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