Exercise · ZW-KERNEL-OF-A-HOMOMORPHISM-005 · ★★☆ Intermediate

Let \(\varphi\colon(\mathbb{Z}_7^{*},\cdot)\to(\mathbb{Z}_7^{*},\cdot)\) with \(\varphi(x)=x^2\). What is its kernel?

Choose one option.

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  • B. \(\{1,6\}\)

Explanation

The identity is \(1\). We need \(x^2\equiv1\pmod 7\): only \(x=1\) and \(x=6\) work (\(6^2=36\equiv1\)).

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Review the concept: Kernel of a homomorphism

The kernel of a group homomorphism \(\varphi\colon G\to H\) is the set of elements of \(G\) that \(\varphi\) sends to the identity \(e_H\) of \(H\).

\[\ker\varphi=\{g\in G:\ \varphi(g)=e_H\}\]

More practice problems: kernel of a homomorphism

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