Exercise · ZW-KERNEL-OF-A-HOMOMORPHISM-009 · ★★★ Advanced
A group \(G\) of order \(15\) maps onto \(\mathbb{Z}_5\) by a surjective homomorphism. How many elements does the kernel have?
Choose one option.
Show answer
- B. 3
Exercise · ZW-KERNEL-OF-A-HOMOMORPHISM-009 · ★★★ Advanced
Choose one option.
Every element of \(\mathbb{Z}_5\) has the same number of preimages, equal to the size of the kernel; so \(15=5\cdot|\ker\varphi|\) and the kernel has \(3\) elements.
The kernel of a group homomorphism \(\varphi\colon G\to H\) is the set of elements of \(G\) that \(\varphi\) sends to the identity \(e_H\) of \(H\).
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