Exercise · ZW-KERNEL-OF-A-HOMOMORPHISM-006 · ★★☆ Intermediate
A homomorphism \(\varphi\colon G\to H\) is injective. What can be stated for sure?
Choose one option.
Show answer
- D. The kernel is \(\{e_G\}\)
Exercise · ZW-KERNEL-OF-A-HOMOMORPHISM-006 · ★★☆ Intermediate
Choose one option.
If \(\varphi(g)=e_H=\varphi(e_G)\), injectivity gives \(g=e_G\); so the kernel is trivial. Surjectivity and equal orders do not follow.
The kernel of a group homomorphism \(\varphi\colon G\to H\) is the set of elements of \(G\) that \(\varphi\) sends to the identity \(e_H\) of \(H\).
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