Explanation

Each is determined by \(a=\varphi(1)\) with \(12a\equiv0\pmod{18}\), i.e. \(a\in\{0,3,\dots,15\}\). The kernel has \(2\) elements when \(a\) has order \(6\): \(a=3\) and \(a=15\).

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Review the concept: Kernel of a homomorphism

The kernel of a group homomorphism \(\varphi\colon G\to H\) is the set of elements of \(G\) that \(\varphi\) sends to the identity \(e_H\) of \(H\).

\[\ker\varphi=\{g\in G:\ \varphi(g)=e_H\}\]

More practice problems: kernel of a homomorphism

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